Previous Year LIC (ADO) RECRUITMENT EXAM SOLVED PAPER

LIC (ADO) RECRUITMENT EXAM SOLVED PAPER

(Held on 10-6-2007)

NUMERICAL ABILITY


Directions—(Q. 1 to 25) What should come in place of the question-mark (?) in the following questions ?
1. 15·36 ´ 2·8 + 7·6 = ?
(A) 326·86 (B) 42·364
(C) 50·608 (D) 36·34
(E) None of these
2. 846 + 281 + (?) + 252 = 681
(A) 446 (B) 698
(C) – 446 (D) – 698
(E) None of these
3. = ?
(A) 0·8 (B) 8·10
(C) 10·5 (D) 0·81
(E) None of these
4. 39114 ÷ 246 ´ ? = 6201
(A) 37 (B) 39
(C) 43 (D) 41
(E) None of these
5. ´ + (85)2 = ?
(A) 7270 (B) 7280
(C) 7260 (D) 7250
(E) None of these
6. (7)3 ´ (3)3 ÷ (6)2 = ?
(A) 12348 (B) 85·75
(C) 1543·5 (D) 257·25
(E) None of these
7. ´ (?) =
(A) (B)
(C) (D)
(E) None of these
8. 39% of ? – 24% of 390 = 171·60
(A) 650 (B) 580
(C) 740 (D) 630
(E) None of these
9. 8736 + 9121 + 4867 + 3308 = ?
(A) 26032 (B) 26320
(C) 23062 (D) 22603
(E) None of these
10. = ?
(A) 59 (B) 67
(C) 61 (D) 57
(E) None of these
11. 7 – 6 = ?
(A) 1 (B) 1
(C) 1 (D) 1
(E) None of these
12. = ?
(A) (B) 4
(C) (D) 2
(E) None of these
13. (666 ´ 66 ´ 6) ÷ ? = 499·5
(A) 462 (B) 532
(C) 540 (D) 396
(E) None of these
14. 3120 + ? ÷ 12·5 = 3563·36
(A) 5542 (B) 5446
(C) 5452 (D) 5354
(E) None of these
15. 449 ´ 367 = ?
(A) 164783 (B) 165681
(C) 164416 (D) 164049
(E) None of these
16. ´ = ?
(A) (B)
(C) (D)
(E) None of these
17. (51)2 – (47)2 + (32)2 = ?
(A) 3786 (B) 2596
(C) 1416 (D) 1296
(E) None of these
18. ÷ 4 ´ 26 = 247
(A) 1764 (B) 1296
(C) 1444 (D) 1369
(E) None of these
19. 0·576 + 2·4 ´ 1·5 = ?
(A) 2·874 (B) 4·276
(C) 2·8824 (D) 4·476
(E) None of these
20. = 17(?)
(A) 1·62 (B) 2·64
(C) 11·1 (D) 29·06
(E) None of these
21. ? + 3229 = 17368 – 4454
(A) 9676 (B) 9445
(C) 9658 (D) 9585
(E) None of these
22. ´ = ?
(A) 2793 (B) 2842
(C) 2679 (D) 2891
(E) None of these
23. ´ ? + 595 = 833
(A) 4480 (B) 4352
(C) 4608 (D) 4096
(E) None of these
24. 815964 – 697826 – 9674 – 6542 = ?
(A) 109122 (B) 101292
(C) 101922 (D) 110922
(E) None of these
25. (7928 – ?) ÷ 84 ´ 12 = 888
(A) 1705 (B) 1698
(C) 1710 (D) 1712
(E) None of these
26. Find out the average of the given numbers.
356, 449, 51, 652, 533, 105, 122
(A) 307 (B) 315
(C) 412 (D) 324
(E) None of these
27. The multiplication of two con-secutive numbers is 8556. What is the smaller number among them ?
(A) 94 (B) 92
(C) 91 (D) 93
(E) None of these
28. An amount of rupees 4500 is to be distributed among Shrikant, Ramakant and Bikrant in the ratio of 3 : 7 : 5 respectively. If Rs. 500 is added to each of the share, the new ratio will become…… ?
(A) 7 : 10 : 13 (B) 9 : 16 : 13
(C) 2 : 4 : 3 (D) 4 : 5 : 2
(E) None of these
29. If (67)2 is added to the square of a number, the addition thus obtained is 6605. What is that number ?
(A) 45 (B) 51
(C) 46 (D) 39
(E) None of these
30. What approximate value should come in place of the question-mark (?) in the following ques-tion ?
7686 ´ 19 ÷ (17)2 = ?
(A) 505 (B) 485
(C) 545 (D) 575
(E) 615
31. If an amount of Rs. 39,856 is distributed equally amongst 18 persons, how much approximate amount would each person get ?
(A) Rs. 2,214 (B) Rs. 2,524
(C) Rs. 2,124 (D) Rs. 2,343
(E) Rs. 2,254
32. The difference between a two-digit number and the number obtained by interchanging the two-digits of the same number is 9. The sum of the digits of the two-digit numbers is 17. What is the product of the two-digits of the two-digit number ?
(A) 64
(B) 63
(C) 72
(D) Cannot be determined
(E) None of these
33. What is 260% of 6680 ?
(A) 18036 (B) 18704
(C) 16700 (D) 17368
(E) None of these
34. What amount of compound interest can be obtained on an amount of Rs. 18,000 at the rate of 10 p.c.p.a. at the end of three years ?
(A) Rs. 5,628 (B) Rs. 5,400
(C) Rs. 5,940 (D) Rs. 5,858
(E) None of these
35. What should come in place of the question-mark (?) in the follow-ing number series ?
19 36 70 ? 274 546
(A) 142 (B) 138
(C) 136 (D) 140
(E) None of these
36. The difference between 60% of a number and 20% of the same numbr is 316. What is 35% of that number ?
(A) 270·5 (B) 285·5
(C) 276·5 (D) 275
(E) None of these
37. The average of 4 positive integers is 52·5. The highest integer is 76 and the lowest integer is 34. The difference between the remain-ing two integers is 4. Which of the following integers is higher of the remaining two integers ?
(A) 52
(B) 54
(C) 48
(D) Cannot be determined
(E) None of these
38. The ratio of the length and the breadth of a rectangular plot is 9 : 8 respectively. The area of the plot is 3528 sq. metres. What is the perimeter of the rectangular plot ?
(A) 256 metres
(B) 119 metres
(C) 238 metres
(D) 126 metres
(E) None of these
39. What is 876 times 779 ?
(A) 68214 (B) 68824
(C) 628402 (D) 682514
(E) None of these
40. The total number of students studying in a school is 10396. The ratio of the total number of girls to the total number of boys studying in the school is 52 : 61 respectively. What is the total number of girls studying in the school ?
(A) 4874 (B) 4784
(C) 5216 (D) 5612
(E) None of these
41. The present age of Mr. Deepak is 3 times the present age of his son. Five years hence the ratio of their ages will be 34 : 13 respecti-vely. What is the present age of Mr. Deepak ?
(A) 63 years (B) 68 years
(C) 58 years (D) 60 years
(E) None of these
42. In an examination it is required to get 36% of the aggregate marks to pass. A student gets 174 marks and is declared failed by 96 marks. What is the maximum aggregate marks a student can get ?
(A) 750
(B) 650
(C) 600
(D) Cannot be determined
(E) None of these
43. In the following number series one number is wrong. Find out the wrong number—
13 16 22 31 42 58
(A) 16 (B) 42
(C) 22 (D) 31
(E) None of these
44. The average of 5 consecutive even numbers A, B, C, D and E is 66. What is the product of B and E ?
(A) 4352 (B) 4340
(C) 4620 (D) 4224
(E) None of these
45. Shri Verma invests Rs. 14500 for 6 years at the certain rate of simple interest. After 6 years his invested sum becomes Rs. 21460. Find out the rate of interest per annum—
(A) 4% p.a. (B) 10% p.a.
(C) 6% p.a. (D) 8% p.a.
(E) None of these
46. The cost of 4 digital cameras and 6 mobile phones is Rs. 51,365. Find out the cost of 12 digital cameras and 18 mobile phones—
(A) Rs. 1,74,500
(B) Rs. 5,13,650
(C) Rs. 1,54,095
(D) Can’t be determined
(E) None of these
47. In how many ways 7 children can be seated in the available 7 seats ?
(A) 4050 (B) 1680
(C) 840 (D) 5040
(E) None of these
48. If x + y = 11 and xy = 28, find out the value of the expression
(x)2 + (y)2.
(A) 63
(B) 56
(C) 65
(D) Can’t be determined
(E) None of these
49. In a canteen 238 kgs. of rice is required for a week. How much rice is required for 49 days ?
(A) 1715 kg (B) 1764 kg
(C) 1568 kg (D) 1617 kg
(E) None of these
50. The circumference of a circular plot is 484 metre. Find out the area of that circular plot—
(A) 15246 metre2
(B) 18634 metre2
(C) 20328 metre2
(D) 13552 metre2
(E) None of these
Answers with Explanations
1. (c) 2. (D) 3. (e) 4. (b) 5. (a)
6. (d) 7. (b) 8. (e) 9. (a) 10. (c)
11. (b) 12. (d) 13. (e) 14. (A) 15. (a)
16. (d) 17. (c) 18. (c) 19. (e) 20. (b)
21. (e) 22. (a) 23. (b) 24. (c) 25. (d)
26. (d)
27. (b) Let the first numbr be ‘n’, then from problem,
n (n + 1) = 8556
n2 + n – 8556 = 0
n2 + 93n – 92n – 8556 = 0
n (n + 93) – 92 (n + 93) = 0
(n + 93) (n – 92) = 0
Either, n = – 93
or n = 92
But the value of n cannot be less than zero i.e. negative.
n = 92
Thus the two numbers are 92 and 93, among them 92 is smaller one.
28. (e) From Problem,
The amount to be given to Shrikant
= = Rs. 900
Similarly Ramakant’s share
= = Rs. 2100
and Bikrant’s share =
= Rs. 1500
Required ratio
= (900 + 500) : (2100 + 500) : (1500 + 500)
= 1400 : 2600 : 2000
= 7 : 13 : 10
29. (C) Let the required number be ‘n’, then from problem,
(67)2 + n2 = 6605
n2 = 6605 – 4489
= 2116
n = = 46
30. (a)
31. (a) From problem,
The amount which is to be given to each of persons
=
= 2214·222 … Rs. 2214
32. (c) Let the original two digit number be (10x + y), where y and x are the unit digit and tens digit respectively.
The number obtained by chang-ing the place of the digits of the original two digit number
= (10y + x)
From problem, we have
(10x + y) – (10y + x) = 9
9 (x – y) = 9
i.e. (x – y) = 1 …(i)
Again from problem,
x + y = 17 …(ii)
Solving equation (i) and (ii), we get
x = 9
and y = 8
\ Required product
= x ´ y
= 9 ´ 8 = 72
33. (d) Required number
= 6680 ´ 2·6
= 668 ´ 26
= 17368
34. (e) We know
A = p t
Here, A = 18000 3
= 18000 ´ 3
= 18 ´ 11 ´ 11 ´ 11
= 23958
\ Compound Interest (C. I.)
= A – p
= 23958 – 18000
= Rs. 5958
35. (b)
36. (c) Let the number be ‘n’, then from problem,
(60% – 20%) of n = 316
40% of n = 316
35% of n = ´ 35
= 276·5
37. (a) Let the 4 positive integers, kept in descending order be a, b, c and d respectively. Then from problem,
a + b + c + d = 4 ´ 52·5
= 210
76 + (b + c) + 34 = 210
(b + c) = 100 …(i)
Again from problem,
b – c = 4 …(ii)
Solving (i) and (ii), we get
b = 52
and c = 48
Required answer = b = 52
38. (c) Let PQRS be any rectangular plot in which its length PQ = 9x mts. and the breadth QR = 8x mts.

From the geometry of the figure,
Area (PQRS) = 9x ´ 8x
3528 = 72 x2
x2 = = 49
x = 7
Perimeter of the rectangular plot
= 2 (9x + 8x)
= 2 ´ 17x
= 34 ´ 7
= 238 metres
39. (e) 779 ´ 876 = 682404
40. (b) From problem,
The total no. of students in the school = 10396
and ratio of no. of girls : boys
= 52 : 61
The total no. of girls in that school
=
=
= 92 ´ 52 = 4784
41. (a) Let the present age of Deepak’s son = x years.
Then from problem,
Deepak’s present age = 3x years
=
39x + 65 = 34x + 170
5x = 105
x = 21
Deepak’s present age = 3x
= 3 ´ 21 = 63 years
42. (a)
43. (b)
Thus in the given no. series 42 is wrong. Instead of 42, the correct no. is = 31 + 12 = 43.
44. (e) From problem,
A + B + C + D + E = 66 ´ 5 = 330
Let the 1st even number A be n, then
n + (n + 2) + (n + 4) + (n + 6) + (n + 8) = 330
5n + 20 = 330
5n = 310
n = 62
Thus the required product
= B ´ E = (n + 2) ´ (n + 8)
= 64 ´ 70 = 4480
45. (d) Using the formula,
S.I. =
(21460 – 14500) =
= r
r = 8
Hence the rate of interest per annum = 8%.
46. (c) From problem,
The cost of 4 Digital Cameras + 6 Mobile Phones = Rs. 51365
The cost of 4 Digital Cameras + 6 Mobile Phones ´ 3 = Rs. 51365 ´ 3
The cost of 12 Digital Cameras and 18 Mobile phones
= Rs. 1,54,095
47. (d)

48. (c) From problem,
x + y = 11,
and xy = 28
Now, (x + y)2 = x2 + y2 + 2xy
(11)2 = x2 + y2 + (2 28)
x2 + y2 = 121 – 56
x2 + y2 = 65.
49. (e) From problem,
Required weight of rice for 49 days
= 238 = 1666 kg
50. (b) Let r be the radius of the circular plot then from problem,

The circumference of the circular plot = 484 m
2pr = 484
r = 484
= 77 metre
Area of the circular plot = pr2
= (77)2
= 18634 m2